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Wave Optics

Question
CBSEENPH12039468

Half-lives of two radioactive elements A and B are 20 minutes and 40 minutes, respectively. Initially, the samples have equal number of nuclei. After 80 minutes, the ratio of decayed numbers of A and B nuclei will be:

  • 1: 16

  • 4 : 1

  • 1: 4

  • 5: 4

Solution

D.

5: 4

Given 80 min = 4 half-lives of A = 2 half-lives of B.
Let the initial number of nuclei in each sample be N.
For radioactive element A,
NA after 80 min = N/24
⇒ Number of A nuclides decayed  =straight N minus straight N over 16 space equals space 15 over 16 straight N


For radioactive element B,
NB after 80 min  = N/22
⇒ Number of B nuclides decayed
straight N minus straight N over 4 space equals space 3 over 4 straight N
therefore, the ratio of decayed numbers of A and B nuclei will be
fraction numerator open parentheses 15 divided by 16 close parentheses straight N over denominator left parenthesis 3 divided by 4 right parenthesis straight N end fraction space equals space 5 over 4

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