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Electrostatic Potential And Capacitance

Question
CBSEENPH12039306

(i) Write the function of a transformer. State its principle of working with the help of a diagram. Mention various energy losses in this device.

(ii) The primary coil of an ideal step-up transformer has 100 turns and the transformation ratio is also 100. The input voltage and power are 220 V and 1100 W, respectively. Calculate the:

a) number of turns in secondary

b) current in primary

c) voltage across secondary

d) current in secondary

e) power in secondary

Solution

i) A transformer is a device that changes a low alternating voltage into a high alternating voltage or vice versa. 
Transformer works on the principle of mutual induction. 
A changing alternate current in primary coil produces a changing magnetic field, which induces a changing alternating current in secondary coil. 
 
Energy losses in transformer: 
Flux leakage due to poor structure of the core and air gaps in the core.
Loss of energy due to heat produced by the resistance of the windings.
Eddy currents due to alternating magnetic flux in the iron core, which leads to loss due to heating. 
Hysteresis, frequent and periodic magnetisation and demagnetization of the core, leading to loss of energy due to heat.
ii)
a)  Number of turns in secondary coil is given by, 

space space space space space space straight N subscript straight s over straight N subscript straight P space equals space n
rightwards double arrow space space N subscript S over 100 space equals space 100 space
rightwards double arrow space space space space space N subscript S space equals space 10 comma 000 
b) Current in primary is given by, 
straight I subscript straight P space straight V subscript straight P space equals space straight P
rightwards double arrow space straight I subscript straight P space equals space 1100 over 220 space equals space 5 space straight A

c) Voltage across secondary  is given by, 
space space space space space space space fraction numerator straight V subscript straight S over denominator space straight V subscript straight P end fraction space equals space N subscript S over N subscript P space equals space n

rightwards double arrow space space space straight V subscript straight S space equals space 100 space straight x space 220 space equals space 22 comma 000 space straight V
d) Current in secondary is given by, 
space space space space space straight V subscript straight S space straight I subscript straight S space equals space straight P

rightwards double arrow space straight I subscript straight S space equals space straight P over straight V subscript straight S space equals space 1100 over 22000 space equals space 0.05 space straight A
e) In an ideal transformer,
Power in secondary = Power in primary = 1,100 W

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