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Wave Optics

Question
CBSEENPH12039374

(i) Obtain the expression for the cyclotron frequency.
(ii) A deuteron and a proton are accelerated by the cyclotron. Can both be accelerated with the same oscillator frequency? Give reason to justify your answer.

Solution

When a charged particle (q) moves inside a magnetic field B with velocity v, it experiences a force F = q(v xB) when v is perpendicular to B, the force F on the charged acts as the centripetal force and makes it move along a circular path.
Let m be the mass of particle and r is radius  of circular path
straight q space left parenthesis straight v with rightwards arrow on top space straight x straight B with rightwards arrow on top right parenthesis space equals space mv squared over straight r
qvB space equals space mv squared over straight r
rightwards double arrow space straight r space equals space mv over Bq
Time period of the circular motion of a charged particle is given by
straight T space equals space fraction numerator 2 πr over denominator straight v end fraction
space equals fraction numerator 2 πmv over denominator straight v space Bq end fraction
rightwards double arrow space straight T space equals space fraction numerator 2 πm over denominator Bq end fraction
Angular space frequency space comma
straight omega space equals space fraction numerator 2 straight pi over denominator straight T end fraction
therefore space straight omega space equals space Bq over straight m
ii) No, The mass of the two particles, i.e deuteron and proton, is different.Since (cyclotron) frequency depends inversely on the mass, they cannot be accelerated by the same oscillator frequency.

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