Define the distance of closest approach. A α-particle of kinetic energy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'r'. What will be the distance of closest approach for a α-particle of double the kinetic energy?

Solution

It is the distance of charged particle from the centre of the nucleus, at
which the whole of the initial kinetic energy of the (far off) charged
particle gets converted into the electric potential energy of the system.
Distance of closest approach (r_c) is given by
$straight r subscript straight c space equals space fraction numerator 1 over denominator 4 πε subscript 0 end fraction. fraction numerator 2 space Ze squared over denominator straight K end fraction$
(r_c) is inversely proportional to K. Thus,
‘K’ is doubled therefore r_c becomes r/2

For Daily Free Study Material Join wiredfaculty

Wave Optics

Define the distance of closest approach. A α-particle of kinetic energy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'r'. What will be the distance of closest approach for a α-particle of double the kinetic energy?

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction