Question
At a place, the horizontal component of earth's magnetic field is B and angle of dip are 60o. What is the value of a horizontal component of the earth's magnetic field at the equator?
Solution
The horizontal component of the electric field is given by
BH = Becos(θ)
where θ is the angle of dip at the given place
Be is teh net magnetic field
At θ = 60o
BH = Be cos(60) = Be x (1/2)
Be = 2BH = 2B (given BH =B)
Now horizontal component at equator
BH = Becos (θ)
angle of dip at equator is 0
BH = Becos(0) = Be = 2B
BH = 2B