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Electric Charges And Fields

Question
CBSEENPH12039356

(a) Explain the meaning of the term mutual inductance. Consider two concentric circular coils, one of radius r1 and the other of radius r2 (r1 < r2) placed coaxially with centres coinciding with each other. Obtain the expression for the mutual inductance of the arrangement.

(b) A rectangular coil of area A, having number of turns N is rotated at ‘ f ’ revolutions per second in a uniform magnetic field B, the field being perpendicular to the coil. Prove that the maximum emf induced in the coil is 2straight pif NBA.

Solution
a) Mutual induction is the property of a pair of coils due to which an emf induced in one of the coils is due to change in the current in the other coil.
Mathematically,
straight M space equals space fraction numerator negative straight e subscript 2 over denominator begin display style bevelled di subscript 1 over dt end style end fraction
Consider two circular coils S1 and S2 of the same length l, such that both their centres coincide with each other.
Let,
n1 is the number of turns per unit length of S1
n2 is the number of tuns per unit length of S2
I1 is the current passed through the solenoid S1
straight ϕ subscript 21 is the flux linked with S2 due to current flowing through S1
We have,
space space space space space straight ϕ subscript 21 space proportional to space straight I subscript 1
rightwards double arrow space straight ϕ subscript 21 space equals space straight M subscript 21 space straight I subscript 1
where,
M21 is the coefficient of mutual induction of the two coils.
When current is passed through S1 an emf is induced in S2.
Magnetic field produced inside S1 on passing current through it is given by,
straight B subscript 1 space equals space straight mu subscript straight o space straight n subscript 1 space straight I subscript 1
Magnetic flux linked with each turn of S2 will be equal to B1 times the area of cross section of S1.
Magnetic flux linked with each turn of S2 = B1A
Therefore,
Total magnetic flux linked with each turn of the S2 is,
space space space space space straight phi subscript 21 space equals space straight B subscript 1 space xA space straight x space straight n subscript 2 straight l
space space space space space space space space space space space space equals straight mu subscript straight o space straight n subscript 1 space straight l subscript 1 space straight x space straight A space straight x space straight n subscript 2 straight l

space space space space space space straight phi subscript 21 space equals straight mu subscript straight o space straight n subscript 1 space straight n subscript 2 space straight A italic space l italic space straight I subscript 1

therefore space straight M subscript 21 space equals space straight mu subscript straight o space straight n subscript 1 space straight n subscript 2 space straight A italic space l italic space
Similarly, mutual induction between the two coils, when current is passed through coil S2 and induced emf is produced in coil S1 is given by,
space space space space straight M subscript 12 space equals space straight mu subscript straight o space straight n subscript 1 space straight n subscript 2 space straight A space l

italic therefore italic space M subscript italic 12 italic space italic equals italic space M subscript italic 21 italic space italic equals italic space M italic space italic left parenthesis s a y italic right parenthesis
Hence, coefficient of mutual induction between the two coil will be,
straight M space equals space straight mu subscript straight o space straight n subscript 1 space straight n subscript 2 space straight A italic space l
b) Flux is given by,
straight ϕ space equals space NBA space cos space straight theta
We know that,
straight e space equals space fraction numerator negative dϕ over denominator dt end fraction space
space space space equals space open parentheses negative NBA left parenthesis negative sinθ right parenthesis dθ over dt close parentheses
For space maximum space emf comma
sinθ space equals space 1
therefore space
straight e subscript max space equals space left parenthesis negative NBA space sin space straight theta space dθ over dt right parenthesis
space space space space space space space space space space equals space NBA space left parenthesis 2 πf space right parenthesis
Hence proved.