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Current Electricity

Question
CBSEENPH12039346

(i) Derive an expression for drift velocity of free electrons.

(ii) How does drift velocity of electrons in a metallic conductor vary with increase in temperature ? Explain.

Solution

i) Expression for the drift velocity of electrons:
When a potential difference is applied across a conductor, an electric field is produced and free electrons are acted upon by an electric force (=-eE).
As a result, electrons accelerate and keep colliding with each other and acquire a constant average velocity (vd).
Therefore,
Fe = -Ee
rightwards double arrow space straight F subscript straight e space equals space fraction numerator negative eV over denominator straight l end fraction
We space know comma
straight a space equals space fraction numerator negative straight F over denominator straight m end fraction equals fraction numerator negative eV over denominator straight m end fraction
Also comma
straight v space equals space straight u plus at

Here comma

straight u space equals space 0 semicolon space
Relaxation space time comma space straight t equals space straight tau

Therefore comma
straight v subscript straight d space equals space minus space aτ
straight v subscript straight d space equals space fraction numerator negative eV over denominator straight m end fraction straight tau
ii) As the temperature is increased, drift velocity of electrons in a metallic conductor increases.
From the above relation,
straight v subscript straight d space proportional to space straight tau
Therefore, as the temperature of the metallic conductor increases, the collision between the electrons and ions increases, resulting in decrease in the relaxation time.
Thus, the drift velocity decreases.

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