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Wave Optics

Question
CBSEENPH12039236

You are given three lenses L1, L2 and L3 each of focal length 20 cm. An object is kept at 40 cm in front of L1, as shown. The final real image is formed at the focus ‘I’ of L3. Find the separations between L1, L2 and L3.

Solution

Given, 
f1 = f2 = f3 = 20 cm 

In case of lens L1,

Object distance, u1 = -40 cm

Using Lens formula,
space space space space space 1 over straight v subscript 1 space minus space 1 over straight u subscript 1 space equals space 1 over straight f subscript 1

rightwards double arrow space 1 over straight v subscript 1 space equals space 1 over 20 space minus space minus 1 over 40

rightwards double arrow space space straight v subscript 1 space equals space 40 space cm
For lens L3,
straight f subscript 3 space equals space 20 space cm. space straight v subscript 3 space equals space 20 space cm

Object space distance comma space straight u subscript 3 space equals space ?

Using space lens space formula comma space we space have

1 over straight v subscript 3 minus 1 over straight u subscript 3 space equals space 1 over straight f subscript 3 space

rightwards double arrow space 1 over 20 minus 1 over straight u subscript 3 space equals space 1 over 20

rightwards double arrow space space 1 over straight u subscript 3 space equals 0 space
rightwards double arrow space space space space straight u subscript 3 space equals space infinity 

So, lens L2 should produce the image at infinity. Thus, objective should be at focus. The image formed by lens L1 is at 40 cm on the right side of lens L1 which lies at 20 cm left of lens L2 i.e., focus of lens L2.

Hence, the distance between L1 and L2 = 40 + 20 = 60 cm.

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