A test charge ‘q’ is moved without acceleration from A to C along the path from A to B and then from B to C in electric field E as shown in the figure. (i) Calculate the potential difference between A and C. (ii) At which point (of the two) is the electric potential more and why?

Solution

i) Potential difference between A and C
$straight V subscript straight C space minus space straight V subscript straight A space equals space minus integral subscript straight A superscript straight C straight E with rightwards harpoon with barb upwards on top space. space dl with rightwards harpoon with barb upwards on top space cos space 180 to the power of straight o space equals space straight E space straight x space 4 space equals space 4 straight E$

ii) Direction of electric field is in higher to lower potential. So, V_c > V_A

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Electrostatic Potential And Capacitance

A test charge ‘q’ is moved without acceleration from A to C along the path from A to B and then from B to C in electric field E as shown in the figure. (i) Calculate the potential difference between A and C. (ii) At which point (of the two) is the electric potential more and why?

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