A proton and an electron have same kinetic energy. Which one has greater de-Broglie wavelength and why?

Solution

As per De-broglies formula,

$straight lambda space equals space fraction numerator straight h over denominator square root of 2 mE subscript straight k end root end fraction$

Kinetic energy of proton is equal to kinetic energy of proton.

Since, mass of proton > mass of electron,

This implies,
$straight lambda subscript straight e space greater than space straight lambda subscript straight p$
That is, wavelength of electron is greater than the wavelength of proton.

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Wave Optics

A proton and an electron have same kinetic energy. Which one has greater de-Broglie wavelength and why?

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