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Wave Optics

Question
CBSEENPH12039272

(a) Using de Broglie’s hypothesis, explain with the help of a suitable diagram, Bohr’s second postulate of quantization of energy levels in a hydrogen atom.

(b) The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?

Solution

a) According to De- broglie hypothesis

straight h over mv equals straight lambda                                   …(i) 

As per De-broglie’s condition of stationary orbits, the stationary orbits are those which contain complete de-Broglie wavelength.

 2 πr space equals space nλ                              ... (ii)                                                    

Putting value of  from equation (i) into (ii)

 

which is the required postulate for Bohr’s quantization of energy levels.

 

b) Given, ground state energy of hydrogen atom = -13.6 eV

Kinetic energy is given by,

 
Potential energy is given by,

 

So, total energy is given by,

Now, from equations (i), (ii) and (iii), we can see that

K.E = - E and U = 2E

We have, E = -13.6 eV

So,

K.E = 13.6 eV

P.E, U = 2 x (-13.6) = -27.2 eV

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