Question
In the given circuit, assuming point A to be at zero potential, use Kirchhoff’s rules to determine the potential at point B.
Solution
Current in 2 resistor is 1 A.
Now, applying Kirchhoff’s law ACDB,
VA + 1 + 2 x 1 - 2 = VB
As, VA = 0
Therefore,
VB = 1 + 2 - 2 = 1 V
