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Wave Optics

Question

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In a Geiger–Marsden experiment, calculate the distance of closest approach to the nucleus of Z =80, when an a-particle of 8 MeV energy impinges on it before it comes momentarily to rest and reverses its direction.

How will the distance of closest approach be affected when the kinetic energy of the a-particle is doubled?

Solution

Let r_o be the distance of closest approach where the kinetic energy of the alpha-particle is converted into it’s potential energy.

Given, Z = 80, E_k = 8 MeV

Since,
$straight r subscript straight o space proportional to space 1 over straight K$

Kinetic energy of the particle becomes doubled if the distance of closest approach becomes half.

Some More Questions From Wave Optics Chapter

In the ground state of electrons are in stable equilibrium, while in electrons always experience a net force. (Thomson's model/Rutherford's model).

A classical atom based on __________ is doomed to collapse. (Thomson's model/Rutherford's model)

An atom has a nearly continuous mass distribution in a ___ but has a highly non-uniform mass distribution in (Thomson's model/Rutherford's model)

The positively charged part of the atom possesses most of the mass in ___________ (Rutherford's model/both the models).

Suppose you are given a chance to repeat the alpha-particle scattering experiment using a thin sheet of solid hydrogen in place of the gold foil. (Hydrogen is a solid at temperatures below 14 K.) What results do you expect?

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