A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38 as shown in the figure. Find the value of the current in circuit. - Wired Faculty

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Current Electricity

Question

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A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38 $straight capital omega$ as shown in the figure. Find the value of the current in circuit.

Solution

Since the cells are in opposition,

E _net= E1 – E₂ = (200-10) = 190 V
So, current in the circuit is given by, I = $straight E subscript net over straight R subscript eq space equals space 190 over 38 space equals space 5 space straight A$

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Current Electricity

A 10 V battery of negligible internal resistance is connected across a 200 V battery and a resistance of 38 $straight capital omega$ as shown in the figure. Find the value of the current in circuit.

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