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Wave Optics

Question
CBSEENPH12039179

(a) Use Huygens' principle to show the propagation of a plane wavefront from a denser medium to a rarer medium. Hence find the ratio of the speeds of wavefront in the two media.

(b) (i) Why does an unpolarized light incident on a polaroid get linearly polarized ?

(ii) Derive the expression of Brewster's law when unpolarized light passing from a rarer to a denser medium gets polarized on reflection at the interface.

Solution

a) 


As seen in the fig. above let XY be a surface separating the two media ‘1’ and ‘2’. Let v1 and v2 be the speeds of waves in these media.

A plane wavefront AB in the first medium is incident obliquely on the boundary surface XY and its end A touches the surface at A at time t = 0 while the other end B reaches the surface at point B after time-interval t.

Here, BB apostrophe space equals space straight v subscript 1 straight t.

As the wavefront AB advances, it strikes the points between A and B’ of boundary surface.

According to Huygens principle, secondary spherical wavelets emanate from these points, which travel with speed v1 in the first medium and speed v2 in the second medium.

Secondary wavelet starting from A, traverses a distance AA’ = v2t in second medium in time t. In the same time, point of wavefront traverses a distance  in first medium and reaches B’, from where the secondary wavelet starts.

So, BB' = v1 t and AA’ = v2t.

Assuming A as centre, we draw a spherical arc of radius AA’ (= v2t) and draw tangent B’A’ on this arc from B’. As the incident wavefront AB advances, the secondary wavelets start from points between A and B’, one after the other and will touch A’B’ simultaneously. 

According to Huygens principle A’B’ is the new position of wavefront AB in the second medium. Hence A’B’ will be the refracted wavefront.

Let the angle made by incident wavefront be i and angle made by the refracted wavefront A’B’ be r.

In space increment space AB apostrophe straight B comma space

space space space space space space space space space space space space space space space space space space space straight angle ABB '  equals straight space 90 to the power of 0

Hence comma space space space space space space space space space space space space space space sin straight space straight i straight space equals straight space sin  ∠ BAB ' 

space space space space space space space space space space space space space space space space space space space space space space space fraction numerator BB straight apostrophe over denominator AB straight apostrophe end fraction equals straight space fraction numerator straight v subscript 1 straight t over denominator AB straight apostrophe end fraction space space space space space space space space space space space space space space space space space space space space... space left parenthesis 1 right parenthesis thin space

Similarly comma space in space right minus angled space triangle comma space angle AA apostrophe straight B comma space
straight angle AA straight apostrophe straight B '  equals straight space 90 to the power of straight o

therefore space space space space space space space space space space space space space space space space space space sin space straight i straight space equals straight space sin    ∠  AB straight apostrophe straight A straight apostrophe

space space space space space space space space space space space space space space space space space space space space space fraction numerator AA straight apostrophe over denominator AB straight apostrophe end fraction equals fraction numerator straight v subscript 2 straight t over denominator AB straight apostrophe end fraction space space space space space space space space space space space space space space space space space space space space space space space... space left parenthesis 2 right parenthesis

Now comma space dividing space equation space left parenthesis 1 right parenthesis space by space left parenthesis 2 right parenthesis comma space we space have space

space space space space fraction numerator sin space straight i over denominator sin space straight r end fraction straight space equals straight space straight v subscript 1 over straight v subscript 2 straight space equals straight space constant

This space is space the space Snell ’ straight s space law space of space refraction.

straight lambda subscript 1 space and space straight lambda subscript 2 space represents space the space wavelength space of space light
space in space the space rarer space medium space and space denser space medium space respectively.

Then comma space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight lambda subscript 1 over straight lambda subscript 2 equals straight space straight v subscript 1 over straight v subscript 2 
b) 

 

Polarization of light is referred to as restricting the vibration of light in a perpendicular direction perpendicular to the direction of propagation of wave.

The vibration of particles of light which is parallel to the axis of crystal passes through the Polaroid on passing an unpolarized light. All other vibrations are absorbed and that is why intensity of emerging light is reduced.
The plane of vibration here is ABCD, in which the vibrations of the polarized light is confined and the plane KLMN is called plane of polarization. KLMN is perpendicular to the plane of vibration.

Reflected light is totally polarized, when unpolarized light is incident on the glass-air interface at the Brewster angle iB. This is known as Brewster’s law.

The reflected component OB and refracted component OC are mutually perpendicular to each other, when light is incident at Brewster’s angle.

italic space italic space italic space italic space italic space italic space angle space B O y space plus space angle Y O C space equals space 90 to the power of o

space space space space space space left parenthesis 90 to the power of 0 space minus space i subscript B right parenthesis space plus space left parenthesis 90 to the power of 0 space plus space r right parenthesis space equals space 90 to the power of o
Now comma space using space Snell ’ straight s space law comma space we space have

space space space space space mu space equals space fraction numerator sin space i over denominator sin space r end fraction 

i = iB and r = (900 – iB)

Therefore, 
mu space equals space fraction numerator sin i subscript B over denominator sin space left parenthesis 90 to the power of o space minus space i subscript B right parenthesis end fraction space equals space fraction numerator sin i subscript B over denominator cos i subscript B end fraction space equals space tan i subscript B , is the expression for Brewster’s law.