Question
Find the equivalent capacitance of the network shown in the figure, when each capacitor is of 1 
F. When the ends X and Y are connected to a 6 V battery, find out
(i) the charge and
(ii) the energy stored in the network
Solution
Equivalent circuit can be drawn as, 
In the above circuit, in one branch there are two capacitors in series.
Therefore, resultant capacitance is, 
The circuit can be further re-arranged as, 
We can see the two capacitors are in parallel.
Therefore, their resultant capacitance is,
Cres = 2 + 2 = 4 
Voltage of the battery = 6V
i) Charge across the capacitor, q = CV = 
ii) Energy stored in the capacitor, E is given by,
