-->

Current Electricity

Question
CBSEENPH12039161

In a meter bridge shown in the figure, the balance point is found to be 40 cm from end A. If a resistance of 10  is connected in series with R, balance point is obtained 60 cm from A. Calculate the values of R and S. 


Solution

For null point, balance length l1 = 40 cm
So, straight R over straight S equals fraction numerator 40 over denominator left parenthesis 100 minus 40 right parenthesis end fraction equals 2 over 3                      ... (1)

If resistance 10 straight capital omega  is connected in series of R, balance point shifts towards AD = 60 cm.
fraction numerator straight R plus 10 over denominator straight S end fraction equals fraction numerator 60 over denominator 100 minus 60 end fraction equals 3 over 2 space space space space space space space space space space... space left parenthesis 1 right parenthesis

space space space straight R over straight S plus 10 over straight S equals 3 over 2 space space space space space space space space space space space space space space space space space space space space space space... space left parenthesis 2 right parenthesis space
From equations (1) and (2), we have

space space space space space space 2 over 3 plus 10 over straight S equals 3 over 2

rightwards double arrow space 10 over straight R equals space 3 over 2 minus 2 over 3 equals space fraction numerator 9 minus 4 over denominator 6 end fraction equals 5 over 6

rightwards double arrow space italic space straight S space equals space fraction numerator 10 cross times 6 over denominator 5 end fraction equals space 12 space o h m 
From equation (1), we have
space space space space straight R over 12 equals 2 over 3

rightwards double arrow space R space equals space fraction numerator 12 space cross times 2 over denominator 3 end fraction equals space 8 space o h m

Some More Questions From Current Electricity Chapter