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Electric Charges And Fields

Question
CBSEENPH12039033

Given a uniform electric field E =5 ×10straight i with hat on top N/C, find the flux of this field through a square of 10 cm on a side whose plane is parallel to the y-z plane. What would be the flux through the same square if the plane makes a 30° angle with the x-axis?                 

Solution

Given, Electric flux,  E with rightwards arrow on top space equals space space 5 space cross times 10 cubed i with hat on top
Error converting from MathML to accessible text.

We have, Electric flux, ϕ = E.A = Error converting from MathML to accessible text. 
                                         = 50 Weber

When the plane makes a 30° angle with the x-axis, the area vector makes 60° with the x-axis

                ϕ = E. A

 ⇒              ϕ=EA cos θ

 ⇒              ϕ= (5×103)(10−2) cos 60°

 ⇒              ϕ=  50 over 2

 ⇒             ϕ = 25 Weber