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Wave Optics

Question
CBSEENPH12039007

In the study of Geiger-Marsdon experiment on scattering of straight alpha particles by a thin foil of gold, draw the trajectory of -particles in the coulomb field of target nucleus. Explain briefly how one gets the information on the size of the nucleus from this study. From the relation straight R space equals space straight R subscript straight o space straight A to the power of begin inline style bevelled 1 third end style end exponent where Ro is constant and A is the mass number of the nucleus, show that nuclear matter density is independent of A. 

Solution


Consider an alpha-particle with initial K.E = 1 half m space v squared directed towards the center of nucleus of an atom.
The force that exists between nucleus and α-particle is Coulomb’s repulsive force. On account of this force, at the distance of closest approach r subscript o , the particle stops and cannot go further closer to the nucleus. And, K.E gets converted to P.E. 
That is, 
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Hence, we can see that the size of the nucleus is approximately equal to the distance of closest approach, ro  .

Now,

If ‘m’ is the average mass of the nucleon and r the radius of nucleus, then

Mass of nucleus = mA; where A is the mass number of the element.
Volume of the nucleus, straight V space equals space 4 divided by 3 space πR cubed
This implies, 
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Therefore, the nuclear density is independent of mass number A.