-->

Wave Optics

Question
CBSEENPH12039006

Write Einstein’s photoelectric equation and mention which important features in photoelectric effect can be explained with the help of this equation. The maximum kinetic energy of the photoelectrons gets doubled when the wavelength of light incident on the surface changes from  straight lambda subscript 1 to straight lambda subscript 2 . Derive the expressions for the threshold wavelength  straight lambda subscript straight o and work function for the metal surface. 

Solution

Einstein’s photoelectric equation is given as: 
hν space equals space straight ϕ subscript straight o plus space straight K. straight E subscript max
where, hstraight nu is the energy of the photon,
straight ϕ subscript straight o, is the work function of the metal,
straight K. straight E subscript max is the maximum kinetic energy of the emitted photoelectron. 

Maximum kinetic energy is given by,
straight K. straight E subscript max space equals space 1 half mv subscript max superscript 2 space equals space hν space minus space straight ϕ subscript straight o space equals space hν space minus space hν subscript straight o ;  
where,straight space straight nu subscript straight o is the threshold frequency of the metal surface.

Features of the equation of photo-electric effect are:

a) When  a photon of suitable radiation falls on the metal surface, a photoelectron is ejected. If the intensity of the light is increased number of photons incident on the metal surface increases and hence, the number of photo-electrons ejected also increases. This implies, photo current is proportional to intensity and radiation.

b) If frequency is less than the threshold frequency, i.e.,  the, photoelectric emission does not take place for incident radiation.

c) When frequency of the incident light is greater than the threshold frequency, maximum K.E increases. This implies, maximum K.E of photoelectrons depends upon the frequency of incident light. 

Einstein’s equation corresponding to wavelength straight lambda subscript 1 space end subscript is comma space 
straight K. straight E subscript max space equals space hc over straight lambda subscript 1 minus straight ϕ subscript straight o space space space space space space space space space space end subscript space space... space left parenthesis 1 right parenthesis 
Einstein’s equation corresponding to wavelength straight lambda subscript 2 is, 
2 straight K. straight E subscript max space equals space hc over straight lambda subscript 2 minus straight ϕ subscript straight o
rightwards double arrow space space space space space straight K. straight E subscript max space equals space fraction numerator hc over denominator 2 straight lambda subscript 2 end fraction minus straight ϕ subscript straight o over 2 space space space space space space space space space space space space space space space... space left parenthesis 2 right parenthesis thin space
 
From equation (1) and (2), we have
Error converting from MathML to accessible text. 
where, straight lambda subscript straight o is the threshold wavelength.  

 

Some More Questions From Wave Optics Chapter