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Wave Optics

Question
CBSEENPH12039002

Find an expression for intensity of transmitted light when a polaroid sheet is rotated between two crossed polaroids. In which position of the polaroid sheet will the transmitted intensity be maximum?

Solution

Let us consider three polaroids A, B and C where C is kept in between A and B.

Using Malu’s Law, the intensity of light emerging from the middle polaroid C is given by,
straight I subscript 1 space equals space straight I subscript straight o cos squared straight theta space semicolon space straight I subscript straight o is straight space the straight space intensity straight space of straight space light straight space falling straight space on straight space middle straight space polaroid.
Therefore, intensity  falls on the polaroid at the end (polaroid B) whose polarisation axis makes an angle of (90 degree space – space straight theta right parenthesis spacewith the polarisation axis of the angle of middle polaroid.

Therefore, Intensity of light emerging from Polaroid B is, 
straight I subscript 2 space equals space straight I subscript 1 cos squared space left parenthesis space 90 minus straight theta right parenthesis

space space space equals space left parenthesis straight I subscript straight o cos squared straight theta right parenthesis space cos squared left parenthesis 90 space minus space straight theta right parenthesis space

italic space italic space italic space equals space straight I subscript o cos to the power of italic 2 θsin to the power of italic 2 straight theta

space space space space equals space fraction numerator 1 over denominator 4 space end fraction straight I subscript 0 space left parenthesis 2 space sinθcosθ right parenthesis squared space
straight I subscript italic 2 space equals space I subscript o over italic 4 sin to the power of italic 2 space 2 straight theta  

That is, transmitted intensity will be maximum when sin 2 straight theta = 1 
2 straight theta space equals space 90 to the power of straight o

rightwards double arrow space space space space space space straight theta space space equals space 45 to the power of straight o