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Wave Optics

Question
CBSEENPH12039001

Use the mirror equation to show that an object placed between f and 2f of a concave mirror produces a real image beyond 2f?

Solution

Mirror formula is given by, 
                             1 over v plus 1 over u space equals space 1 over f

where,
u is the distance of the object from the mirror,

v is the distance of image from the mirror, and

f is the focal-length of the mirror. 

For a concave mirror, f < 0.

Object distance is negative for an object on the left side. i.e., u< 0.

Given, f < u <2f.

Subtracting throughout from 1 over f, we get
1 over f minus fraction numerator 1 over denominator 2 f end fraction greater than 1 over f minus 1 over u greater than 1 over f minus 1 over f
fraction numerator 1 over denominator 2 f end fraction space less than space 1 over v space less than thin space 0

Therefore, the image formed is negative and is on the left side.

Also, the inequality implies, 2f > v. i.e., |2f| < |v|. 

That is, the real image is formed beyond 2f. 





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