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Electrostatic Potential And Capacitance

Question
CBSEENPH12039099

Two uniformly large parallel thin plates having charge densities +straight sigma and –sigmaare kept in the X-Z plane at a distance 'd' apart. Sketch an equipotential surface due to electric field between the plates. If a particle of mass m and charge '-q' remains stationary between the plates, what is the magnitude and direction of this field? 

Solution

Equipotential surface between the plates due to the electric field is given by the figure shown below. We can see that, the equipotential surface is at a distance d/2 from either plate in X-Z plane.

Given, a particle of mass ‘m’ and charge ‘-q’ remains stationary in between the plates. For the negative charge,

i) weight mg acts, vertically downward

ii) electric force qE acts vertically upward.

So, mg = qE
rightwards double arrow space E space equals space fraction numerator m g over denominator q end fraction, is acting vertically downwards (along –Y axis).

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