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Current Electricity

Question
CBSEENPH12039069

A cell of emf E and internal resistance r is connected to two external resistances R1 and R2 and a perfect ammeter. The current in the circuit is measured in four different situations:

(i) without any external resistance in the circuit.

(ii) with resistance R1 only

(iii) with R1 and R2 in series combination

(iv) with R1 and R2 in parallel combination.

The currents measured in the four cases are 0.42 A, 1.05 A, 1.4 A and 4.2 A, but not necessarily in that order. Identify the currents corresponding to the four cases mentioned above.      

Solution

The current in the circuit to corresponding situations is given by:

 

i) When there is no external resistance in the circuit, 
               straight I subscript 1 straight space equals straight space straight E over straight r

The current in this case will be maximum because effective resistance is minimum. So, I1 = 4.2 A 

ii) In the presence of resistance R1 only, we have
             I subscript 2 space equals space fraction numerator E over denominator r plus R subscript 1 end fraction

Here, effective resistance is more than (i) and (iv) but less than (iii).

So, I2 = 1.05 A
iii) When R1 and R2 are in series combination, we have
            straight I subscript 3 straight space equals straight space fraction numerator straight E over denominator straight r plus left parenthesis straight R subscript 1 plus straight R subscript 2 right parenthesis end fraction
In this case, effective resistance is maximum, so current is minimum.

Thus, I3 = 0.42 A
iv) When R1 and R2 are in parallel combination, we have
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Here, effective resistance is more than (i) but less than (ii) and (iii).

So, I4 = 1.4 A