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Wave Optics

Question
CBSEENPH12039043

A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. Upto which energy levels the hydrogen atoms would be excited?

Calculate the wavelengths of the first member of Lyman and first member of Balmer series. 

Solution

Amount of energy required to excite the electron = 12.5 eV
Energy of the electron in the nth state of an atom = negative fraction numerator 13.6 straight space straight z squared over denominator straight n squared end fraction straight space eV ; Z is the atomic number of the atom. [Z=1 for hydrogen atom]
Energy required to excite an atom from the initial state (ni) to the final state (nf) = negative fraction numerator 13.6 over denominator straight n subscript straight f squared end fraction plus fraction numerator 13.6 over denominator straight n subscript straight i squared end fraction

This energy must be equal to or less than the energy of the incident electron beam.

 

negative straight space fraction numerator 13.6 over denominator straight n subscript straight f squared end fraction plus fraction numerator straight space 13.6 over denominator straight n subscript straight i to the power of straight space 2 end exponent end fraction straight space equals straight space 12.5 straight space   … (1)

i=1 for ground state of hydrogen atom.

 

Energy of the electron in the ground state = −13.6 eV

Now, putting this in equation (1),
therefore space minus straight space fraction numerator 13.6 over denominator straight n subscript straight f squared end fraction space plus space 13.6 space equals space 12.5 space

rightwards double arrow space 13.6 space minus space 12.5 space equals space minus straight space fraction numerator 13.6 over denominator straight n subscript straight f squared end fraction

rightwards double arrow space straight n subscript straight f squared straight space equals straight space fraction numerator 13.6 over denominator 1.1 end fraction straight space equals straight space 12.36

rightwards double arrow space straight n subscript straight f space equals space 3.5 

Since, the state cannot be a fractional number we have nf = 3

Therefore, hydrogen atom would be excited up to 3rd energy level. 
b) Rydberg formula is given by, Error converting from MathML to accessible text. ;  straight lambda spaceis the wavelength and R is the Rydberg constant. 
R = 1.097373157 × 10 7 m-1  

For the first member of Lyman series, i=1; f=2 
So, Error converting from MathML to accessible text.
rightwards double arrow bold lambda space equals space 1215 space cross times 10 to the power of negative 11 end exponent
For the first member of the Balmer series, i=2; f=3 
So, 
Error converting from MathML to accessible text.