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Wave Optics

Question
CBSEENPH12038999

Show that the radius of the orbit in hydrogen atom varies as , where n is the principal quantum number of the atom. 

Solution

The electrostatic force of attraction between nucleus and the electron is, 
                                                straight F equals ke squared over straight r

According to Bohr’s theory, a hydrogen atom consists of a nucleus with a positive charge e and a single electron of charge –e, which revolves around it in circular orbit of radius r.

To keep electron bound to its orbit, centripetal force on the electron becomes equal to the electrostatic attraction. Therefore, 
space space space space space space space space space space space space space space space mv squared over straight r equals ke squared over straight r space

space space space space space space space space space space space space space space space space space mv squared space equals space ke squared over straight r

rightwards double arrow space space space space space space space space space space space space space space space italic space space straight r space equals space italic ke to the power of italic 2 over italic mv to the power of italic 2 italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic space italic. italic. italic. italic space italic left parenthesis italic 1 italic right parenthesis

where,
m is the mass of electron, and

v is the speed of an orbit of radius r. 

Now, using  Bohr’s  quantisation condition for angular momentum,

straight L straight space equals straight space mvr straight space equals straight space fraction numerator nh over denominator 2 straight pi end fraction

rightwards double arrow space space space space space space space straight v straight space equals straight space fraction numerator nh over denominator 2 πmr end fraction space space space space space space space space space space... space left parenthesis 2 right parenthesis thin space

Putting space left parenthesis 2 right parenthesis space in space equation space left parenthesis 1 right parenthesis comma space we space have

straight r straight space equals straight space fraction numerator ke squared over denominator straight m left parenthesis fraction numerator nh over denominator 2 πmr end fraction right parenthesis squared end fraction

space straight r equals straight space fraction numerator ke squared over denominator fraction numerator mn squared straight h squared over denominator 4 straight pi squared straight m squared straight r squared end fraction end fraction

   straight r straight space equals straight space fraction numerator ke squared over denominator mn squared straight h squared end fraction left parenthesis 4 straight pi squared straight m squared straight r squared right parenthesis

   straight r straight space equals straight space fraction numerator straight n squared straight h squared over denominator 4 straight pi squared mke squared end fraction

space space space straight r straight space proportional to straight space straight n squared  
where, n is the principal quantum number.