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Electrostatic Potential And Capacitance

Question
CBSEENPH12038988

(a) Draw a schematic sketch of a cyclotron. Explain clearly the role of crossed electric and magnetic field in accelerating the charge. Hence derive the expression for the kinetic energy acquired by the particles.

(b) An –particle and a proton are released from the centre of the cyclotron and made to accelerate.

(i) Can both be accelerated at the same cyclotron frequency? Give reason to justify your answer.

(ii) When they are accelerated in turn, which of the two will have higher velocity at the exit slit of the dees? 

Solution

a)
The schematic sketch of cyclotron is as shown below:
 

Electric field: It helps in accelerating the charged particle passing through the gap with the help of electric oscillator. Electric oscillator imparts the energy to charged particle till it comes out from the exit slit.

Magnetic field: The magnetic force exerts a centripetal force when the accelerated charge particle enters normally to the uniform magnetic field. Centripetal force makes the particle move in a semicircular path of increasing radii in each Dee.
Kinetic energy acquired by the particle is given by, 

space space space space space space space space space qvB space equals space mv squared over straight r space space space space space
rightwards double arrow space space space space space space space space straight v space equals space qBr over straight m space space space space space space space space space space space space space... space left parenthesis 1 right parenthesis thin space

Kinetic space Energy comma space straight K. straight E space equals space 1 half mv squared space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator straight q squared straight B squared straight r squared over denominator 2 straight m end fraction space space space space space space space... space left parenthesis 2 right parenthesis space
 
b) 

i) Now, using equation (1), we have
space space space space space space space straight v space equals space qBr over straight m space
rightwards double arrow space space straight v space equals space rω space equals space qBr over straight m
rightwards double arrow space space 2 πν space equals space qB over straight m
rightwards double arrow space space space space space space space space straight nu space equals space fraction numerator qB over denominator 2 πm end fraction
 
Here we can see that, cyclotron frequency depends upon (q/m) ratio.

So, 
open parentheses straight q over straight m close parentheses subscript alpha space less than thin space open parentheses straight q over straight m close parentheses subscript straight p 

That is, 
straight v subscript straight alpha space less than thin space straight v subscript straight p 

ii) Kinetic energy is given by, 
straight K space equals space fraction numerator straight q squared straight B squared straight r squared over denominator 2 straight m end fraction 

That is, 
open parentheses straight q squared over straight m close parentheses subscript p r o t o n end subscript space greater than thin space open parentheses straight q squared over straight m close parentheses subscript straight alpha
That is, proton acquires higher velocity.

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