For a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 2 V. If the current amplification factor of the transistor is 100, calculate (i) input signal voltage
(ii) base current. Given that the value of the base resistance is 1 kΩ.

Solution

(i) Given,
Collector resistance, R_c = 2 k $Ω$
Audio signal voltage, V_o = 2 V
Current amplification factor, $β$ = 100

Now, using the formula,

$A_{v} = β \frac{R_{C}}{R_{B}} \Rightarrow A_{v} = 100 \times \frac{2000}{1000} = 200$

Output voltage, V_o= $A_{v} \times V_{i}$

$\Rightarrow$ $V_{i} = \frac{V_{0}}{A_{v}} = \frac{2}{200} = \frac{1}{100} V = 0.01 V$
is the input signal voltage.

(ii) Now, current amplification factor, $β = \frac{I_{C}}{I_{B}}$

$\Rightarrow$ Base current, $I_{B} = \frac{I_{C}}{β} = \frac{V_{0}}{R_{c}} \times \frac{1}{β}$

$= \frac{2}{2000 \times 100} = \frac{1}{10^{5}} A = 10^{- 5} A$

$\Rightarrow$    $I_{B} = 10 \times 10^{- 6} A = 10 μA .$

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Wave Optics

For a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 2 V. If the current amplification factor of the transistor is 100, calculate (i) input signal voltage
(ii) base current. Given that the value of the base resistance is 1 kΩ.

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For Daily Free Study Material Join wiredfaculty

Wave Optics

For a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 2 V. If the current amplification factor of the transistor is 100, calculate (i) input signal voltage(ii) base current. Given that the value of the base resistance is 1 kΩ.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

For a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2 k Ω is 2 V. If the current amplification factor of the transistor is 100, calculate (i) input signal voltage
(ii) base current. Given that the value of the base resistance is 1 kΩ.