Calculate the value of V₀ and I if the Si diode and the Ge diode conduct at 0.7V and 0.3V respectively, in the circuit given in figure. If now Ge diode connections are reversed, what will be the new values of V_o and I.

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Solution

As in the given circuit,

Voltage, V = 12 V
Resistance, R = 5 k

Ω

Therefore,

Current,

I = \frac{12 - 0.3}{5 k Ω} = \frac{11.7 V}{5 \times 10^{3} Ω}

= 2.34 mA

Output voltage,

V_{0} = RI = (5 \times 10^{3}) \times (2.34 \times 10^{- 3}) = 11.7 V

When the connections of Ge diode are reversed, then current will be through silicon.

In this case,

Current,

I = \frac{(12 - 0.7) V}{5 k Ω} = \frac{11.3 V}{5 \times 10^{- 3} Ω} = 2.26 mA

Therefore,

Output voltage, V_{0} = IR = (2.26 \times 10^{- 3}) \times (5 \times 10^{3}) = 11.3 V .

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