Wave Optics

Question

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From the output characteristics shown in figure calculate the values of current amplification factor of the transistor when V_CE is 2V.

Solution

Given,
V_CE = 2 V
Current amplification factor, $β = {(\frac{∆ I_{C}}{∆ I_{B}})}_{V_{CE}}$

Consider characteristics for any two values of I_B (say, 10 and 60 μA).
Then for V_CE = 2 V from the graph,

we have, $∆ I_{B} \approx (60 - 10) μA = 50 μA ∆ I_{C \approx} (9.5 - 2.5) mA = 7.0 mA$

Therefore, $β = (\frac{7 \times 10^{- 3} A}{50 \times 10^{- 6} A}) = 140 .$

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Wave Optics

From the output characteristics shown in figure calculate the values of current amplification factor of the transistor when V_CE is 2V.

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For Daily Free Study Material Join wiredfaculty

Wave Optics

From the output characteristics shown in figure calculate the values of current amplification factor of the transistor when VCE is 2V.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

From the output characteristics shown in figure calculate the values of current amplification factor of the transistor when V_CE is 2V.