A change of 8.0 mA in the emitter current brings a change of 7.6 mA in the collector current. How much change in the base current is required to have the same change (= 7.6 mA) in collector current. Find the value of a and β.

Solution

Given,

$Change in emitter current, ∆ I_{e} = 8.0 mA C hange in collector current, ∆ I_{c} = 7.6 mA$

As, change in emitter current, $∆ I_{e} = ∆ I_{b} + ∆ I_{c}$

This implies,
Change in base current, $∆ I_{b} = ∆ I_{e} - ∆ I_{c}$
$= 8.0 - 7.6 = 0.4 mA$

$α = \frac{∆ I_{c}}{∆ I_{e}} = \frac{7.6}{8.0} = 0.95$ and

$β = \frac{∆ I_{c}}{∆ I_{b}} = \frac{7.6}{0.4}$

i.e., $β = 19 .$

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Wave Optics

A change of 8.0 mA in the emitter current brings a change of 7.6 mA in the collector current. How much change in the base current is required to have the same change (= 7.6 mA) in collector current. Find the value of a and β.

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