The number of silicon atoms per m³ is 5 x 10²⁸. This is doped simultaneously with 5 x 10²² atoms per m³ of Arsenic and 5 x 10²⁰ per m³ atoms of Indium. Calculate the number of electrons and holes. Given that n_i = 1.5 x 10¹⁶ m^–3. Is the material n-type or p-type?

Solution

Number of Arsenic atoms per m³ =5 x 10²²
Number of Indium atoms per m³ = 5

\times

10²⁰
Intrinsic concentration, n_i= 1.5 x 10¹⁶ m^–3Therefore,

Number of electrons, n_e = 5 x 10²² – 5 x 10²⁰

= (5 – 0.05) x 10²²

^{Now, number of holes is, $n_{h} = \frac{n_{i}^{2}}{n_{e}}$

$= \frac{(1.5 \times 10^{16})}{4.95 \times 10^{22}} = 4.54 \times 10^{9} m^{- 3}$}Since, n_e > n_h, so the material is n-type semiconductor.

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The number of silicon atoms per m³ is 5 x 10²⁸. This is doped simultaneously with 5 x 10²² atoms per m³ of Arsenic and 5 x 10²⁰ per m³ atoms of Indium. Calculate the number of electrons and holes. Given that n_i = 1.5 x 10¹⁶ m^–3. Is the material n-type or p-type?

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The number of silicon atoms per m³ is 5 x 10²⁸. This is doped simultaneously with 5 x 10²² atoms per m³ of Arsenic and 5 x 10²⁰ per m³ atoms of Indium. Calculate the number of electrons and holes. Given that n_i = 1.5 x 10¹⁶ m^–3. Is the material n-type or p-type?