In the series of radioactive disintegration of ${}_{Z}^{A}X$ first one α-particle and then one β-particle is emitted. What is the atomic number and mass number of the new nucleus formed by these successive disintegrations?

Solution

When an alpha particle is emitted, mass number decreases by 2 and atomic number decreases by 2 and when a beta particle is emitted, mass number remains the same and atomic number increases by 1.

$∴ {}_{Z}^{A}X \overset{α}{\to} {}_{Z - 2}^{A - 4} X \overset{β}{\to} {}_{Z - 1}^{A - 4}X$

So, mass number becomes (A-4) and atomic number becomes (Z-1).

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Wave Optics

In the series of radioactive disintegration of ${}_{Z}^{A}X$ first one α-particle and then one β-particle is emitted. What is the atomic number and mass number of the new nucleus formed by these successive disintegrations?

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Wave Optics

In the series of radioactive disintegration of XZA first one α-particle and then one β-particle is emitted. What is the atomic number and mass number of the new nucleus formed by these successive disintegrations?

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

In the series of radioactive disintegration of ${}_{Z}^{A}X$ first one α-particle and then one β-particle is emitted. What is the atomic number and mass number of the new nucleus formed by these successive disintegrations?