The half-life of ${}_{92}^{238}U$ against $α - decay$ is 4.5 × 10⁹ years. Calculate the activity of 1g sample of ${}_{92}^{238}U .$

Name: Wired Faculty - The Best Learning App
Rating: 4.6 (1864 reviews)

Solution

Given,

Half life of Uranium, T_{1 / 2} = 4.5 \times 10^{9} years = 4.5 \times 10^{9} \times 3.156 \times 10^{7} s

Number of atoms in 1g of uranium,

N = \frac{6.023 \times 10^{23}}{238} atoms

Activity of the sample =

λN

= \frac{0.693}{T_{1 / 2}} \times N

= \frac{0.693 \times 6.023 \times 10^{23}}{4.5 \times 3.156 \times 10^{16} \times 238}

= 1.235 \times 10^{4} disintegration / second .

For Daily Free Study Material Join wiredfaculty