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Wave Optics

Question

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Explain, with the help of a nuclear reaction in each of the following cases, how the neutron to proton ratio changes during β-decay?

Solution

Alpha-decay of Bismuth is shown below:

{}_{83}^{210}{Bi} \to {}_{84}^{210}{Po} + {}_{- 1}^{0}e

Neutron to proton ratio before

β - decay

= \frac{210 - 83}{83} = \frac{127}{83}

Neutron to proton ratio after

β - decay

= \frac{210 - 84}{84} = \frac{126}{84}

Since,

\frac{126}{84} < \frac{127}{83}

Thus, the neutron to proton ratio decreases in a

β - decay .

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