Explain, with the help of a nuclear reaction in each of the following cases, how the neutron to proton ratio changes during α-decay.

Solution

The $α$ -decay of Uranium is given by,

${}_{92}^{238}U \to {}_{90}^{234}{Th} + {}_{2}^{4}{He}$

Neutron to proton ratio before $α - decay$ $= \frac{238 - 92}{92} = \frac{146}{92}$

Neutron to proton ratio after $α - decay$ $= \frac{234 - 90}{90} = \frac{144}{90}$

Since, $\frac{144}{90} > \frac{146}{92}$

Thus, the neutron to proton increases is an $α - decay$ .

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Explain, with the help of a nuclear reaction in each of the following cases, how the neutron to proton ratio changes during α-decay.

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