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Wave Optics

Question
CBSEENPH12038706

Define the term decay constant of a radioactive nucleus.
Two nuclei P, Q have equal number of atoms at t = 0. Their half lives are 3 hours and 9 hours respectively. Compare their rates of disintegration, after 18 hours from the start.

Solution
Decay constant of a radioactive element is the reciprocal of the time during which the number of atoms left in the sample reduces to 1e times the number of atoms in the original sample. 

Given, two nucleii  P and Q. 
P and Q have equal number of atoms at t=0. 
Half life of P = 3 hours. 
Half life of Q = 9 hours. 

and, t = 18 hours

Number of half lives of P in 18 hours  =tT12183=6 

Number of nuclei P left undecayed after 6 half lives is, 
                      N1 = N126 

Number of half lives of Q in 18 hours=tT12 = 189=2 

Number of nuclei of Q left undecayed after 2 half lives is, 

                       N2 = N122 

Ratio of their decay rate is, 

               R1R2 = λ1 N1λ2 N2 = T2 N1T1 N2 

  R = λ N and T = 0.693λ 

               R1R2 = 93×N126N122 = 316 

Hence ratio of disintegration is, R1:R2 = 3 :16

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