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Wave Optics

Question

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What will be the total energy of an electron in hydrogen atom in third orbit. (Take total energy of electron in its ground state in – 13.6 eV).

Solution

In the third orbit, n =3

For hydrogen atom, energy of an electron is given by,

E_n = $\frac{- 13.6}{n^{2}} = - \frac{13.6}{3^{2}} = \frac{- 13.6}{9} = - 1.5 e V$

Some More Questions From Wave Optics Chapter

Answer the following questions, which help you understand the difference between Thomson's model and Rutherford's model better.
Is the probability of backward scattering (i.e., scattering of α-particles at angles greater than 90°) predicted by Thomson's model much less, about the same, or much greater than that predicted by Rutherford's model?

Answer the following questions, which help you understand the difference between Thomson's model and Rutherford's model better.
Keeping other factors fixed, it is found experimentally that for small thickness t, the number of α-particles scattered at moderate angles is proportional to t. What clue does this linear dependence on t provide?

Answer the following questions, which help you understand the difference between Thomson's model and Rutherford's model better.
In which model is it completely wrong to ignore multiple scattering for the calculation of average angle of scattering of α-particles by a thin foil?

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