The energy levels of hydrogen atoms are as shown in Fig. Which of the shown transition will result in the emission of a photon of wavelength 275 nm?
Which of the transition corresponds to emission of radiation of (i) maximum and (ii) minimum wavelength?

Solution

Wavelength of photon,

λ

= 275 nm

Therefore,
Energy of the photon is given by,

∆ E = \frac{hc}{λ} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{275 \times 10^{- 9}} J = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{275 \times 10^{- 9} \times 1.6 \times 10^{- 19}} eV = \frac{6.6 \times 3}{275 \times 1.6} \times 10^{2} eV = 6.0 eV

As shown in the fig. ,

i) Maximum radiation is emitted in transition A.

ii) Minimum radiation is emitted in transition D.

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