A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of ${}_{29}^{63}{Cu} atoms$ (of mass 62.92960 u).

Solution

Given, mass of the coin = 3.0 g

Mass of atom = 62.92960 u

Each atom of the copper contains 29 protons and 34 neutrons.

Mass of 29 electrons = 29 x 0.000548 u
= 0.015892 u

Mass of nucleus = (62.92960 - 0.015892) u

= 62.913708 u

Mass of 29 protons = 29 x 1.007825 u
= 29.226925 u

Mass of 34 neutrons = 34 x 1.008665 u

= 34.29461 u
Total mass of protons and neutrons = (29.226925 + 34.29461) u
= 63.521535 u

Binding energy = (63.521535 - 62.913708) x 931.5 MeV
= 0.607827 x 931.5 MeV

$∴$ Required energy = $\frac{6.023 \times 10^{23}}{63} \times 3 \times 0.607827 \times 931.5 MeV$
$= 1.6 \times 10^{25} MeV = 2.6 \times 10^{12} J .$

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A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of ${}_{29}^{63}{Cu} atoms$ (of mass 62.92960 u).

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A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of Cu2963 atoms (of mass 62.92960 u).

Some More Questions From Wave Optics Chapter

Mock Test Series

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A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of ${}_{29}^{63}{Cu} atoms$ (of mass 62.92960 u).