-->

Wave Optics

Question
CBSEENPH12038569

In accordance with the Bohr's model, find the quantum number that characterises the earth's revolution around the sun in an orbit of radius 1.5 × 1011 m with orbital speed 3 × 104m/s. (Mass of earth = 6.0 × 1024 kg.)

Solution
Given, 
Radius of the orbit, r = 1.5 × 1011 m 
Orbital speed, v = 3 × 104m/s. 
Mass of the earth, m = 6.0 × 1024 kg

Now, according to Bohr's theory
                   mvr = nh2π 

or,                   n= 2π mvrh 
                    

                       
                         = 2.56 × 1074.