Question
In Young's double-slit experiment how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringe if λ = 2000 Å and d = 7000Å. Given that perpendicular distance of a screen from the mid-point of two slits is 3.5 cm.
Solution
For,
Wavelength, λ = 2000 Å
Distance between the slits, d = 7000Å
Perpendicular distance of a screen from the mid point of two slits = 3.5 cm
Maximum intensity on the screen
i.e.,
Since,
Thus, a total of only seven maximas can be obtained on both sides of the screen.
Wavelength, λ = 2000 Å
Distance between the slits, d = 7000Å
Perpendicular distance of a screen from the mid point of two slits = 3.5 cm
Maximum intensity on the screen
i.e.,
Since,
Thus, a total of only seven maximas can be obtained on both sides of the screen.
