Question
In a double-slit experiment, two coherent sources have slightly different intensities I and (I + δI), such that δ << I, show that resultant intensity at maxima is near 4I, while that at minima is nearly (δl)2/4l.
Solution
Given, Young's double slit experiment with two coherent sources.
Intensity of first source, I1 = I
Intensity of second source, I2 = I + δI
Now, using the formula for resultant intensity,
For maxima,
As therefore,
For minima,
Hence proved.