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Wave Optics

Question

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What is the de-Broglie wavelength associated with an electron accelerated through a potential of 100 volts?

Solution

Accelerating potential, v = 100 V

De-Broglie wavelength is given by,

λ = \frac{1.227}{\sqrt{V}} nm

\Rightarrow

λ = \frac{1.227}{\sqrt{100}} nm = 0.123 nm .

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