The frequency (v) of the incident radiation is greater than threshold frequency (v₀) in a photocell. How will the stopping potential vary if frequency v is increased, keeping other factors constant?

Solution

Given, the frequency of the incident radiation is greater than the threshold frequency.

The formula gives us, $\frac{1}{2} {mv}_{\max}^{2} = {eV}_{0} = h (v - v_{0})$

Therefore, the value of stopping potential (V₀) increases with increase in frequency (v) of the incident radiation and K.E. increaseses.

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The frequency (v) of the incident radiation is greater than threshold frequency (v₀) in a photocell. How will the stopping potential vary if frequency v is increased, keeping other factors constant?

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Wave Optics

The frequency (v) of the incident radiation is greater than threshold frequency (v0) in a photocell. How will the stopping potential vary if frequency v is increased, keeping other factors constant?

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The frequency (v) of the incident radiation is greater than threshold frequency (v₀) in a photocell. How will the stopping potential vary if frequency v is increased, keeping other factors constant?