Question
Ultraviolet light is incident on two photosensitive materials having work functions W1 and W2 (W1 > W2). In which case will the kinetic energy of the emitted electrons be greater? Why?
Solution
According to the formula,
K.E. of photoelectron = hv – W
That is, more is the kinetic energy less would be the work function or vice-cersa.
Given, W1 > W2 (W1 and W2 are the work function of material respectively.)
Since, W2 is lesser than W1 thus, the kinetic energy of the emitted electrons for the photoelectric material having work function W2 will be greater.
K.E. of photoelectron = hv – W
That is, more is the kinetic energy less would be the work function or vice-cersa.
Given, W1 > W2 (W1 and W2 are the work function of material respectively.)
Since, W2 is lesser than W1 thus, the kinetic energy of the emitted electrons for the photoelectric material having work function W2 will be greater.
