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Wave Optics

Question

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Two metals A and B have work function 2 eV and 5 eV respectively. Which metal has lower threshold wavelength?

Solution

Given, work function of metal A = 2 eV
Work function of metal B = 5 eV

As, $ϕ_{0} = \frac{hc}{λ} \Rightarrow λ = \frac{hc}{ϕ_{0}}$

i.e. $λ \propto \frac{1}{ϕ_{0}}$

Thus, metal B has lower threshold wavelength of radiation since its work function is greater.

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