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Wave Optics

Question
CBSEENPH12038493

de-Broglie wavelength associated with an electron accelerated through a potential difference V is X. What will be its wavelength when the accelerating potential is increased to 4 V?

Solution
De-Broglie wavelength assosciated with an electron is,
           λ = 1.227Vnm
That is, wavelength is inversely proportional to the square -root of potential.
Thus,
When potential difference is increased 4 times,wavelength becomes half it's value. 

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