Obtain the de-Broglie wavelength of a neutron of kinetic energy 150 eV. As you have seen in Question 11.31, an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. Given (m_n = 1.675 x 10^–27 kg.)

Solution

Here,
Kinetic energy, K.E. of neutron, E = 150 eV = 150 x 1.6 x 10^–19 J,
Mass of neutron, m = 1.675 x 10^–27 kg.

We know, K.E. of neutron,

E = \frac{1}{2} {mv}^{2} or mv = \sqrt{2 Em}

∴

λ = \frac{h}{mv} = \frac{h}{\sqrt{2 Em}}

= \frac{6.63 \times 10^{- 34}}{\sqrt{2 \times 150 \times 1.6 \times 10^{- 19} \times 1.675 \times 10^{- 27}}} = 2.33 \times 10^{- 12} m .

The interatomic spacing ~ 1 Å (= 10^–10 m) is about a hundred times greater than this wavelength. Therefore, a neutron beam of energy 150 eV is not suitable for diffraction experiment.

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Wave Optics

Obtain the de-Broglie wavelength of a neutron of kinetic energy 150 eV. As you have seen in Question 11.31, an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. Given (m_n = 1.675 x 10^–27 kg.)

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For Daily Free Study Material Join wiredfaculty

Wave Optics

Obtain the de-Broglie wavelength of a neutron of kinetic energy 150 eV. As you have seen in Question 11.31, an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. Given (mn = 1.675 x 10–27 kg.)

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Obtain the de-Broglie wavelength of a neutron of kinetic energy 150 eV. As you have seen in Question 11.31, an electron beam of this energy is suitable for crystal diffraction experiments. Would a neutron beam of the same energy be equally suitable? Explain. Given (m_n = 1.675 x 10^–27 kg.)