A monoenergetic electron beam with electron speed of 5.20 x 10⁶ ms^–3 is subject to a magnetic field of 1.30 x 10^–4 T normal to the beam velocity. What is the radius of the circle traced by the beam, given e/m for electron equals 1.76 x 10¹¹C kg^–1.

Solution

Given,
Velocity of electron, v = 5.20 x 10⁶ m/s
Magnetic field, B = 1.30 x 10^–4 T
specific charge ratio, e/m = 1.76 x 10¹¹ C kg^–1Centripetal force is provided by the force exerted by magnetic field on electron,

$∴$ $\frac{{mv}^{2}}{r} = Bev$

$\Rightarrow$ $r = \frac{mv}{Be} = \frac{v}{B (e / m)}$

$\Rightarrow$ $r = \frac{5.20 \times 10^{6}}{1.30 \times 10^{- 4} \times 1.76 \times 10^{11}} m$
$= 0.227 m = 22.7 cm .$

For Daily Free Study Material Join wiredfaculty

Wave Optics

A monoenergetic electron beam with electron speed of 5.20 x 10⁶ ms^–3 is subject to a magnetic field of 1.30 x 10^–4 T normal to the beam velocity. What is the radius of the circle traced by the beam, given e/m for electron equals 1.76 x 10¹¹C kg^–1.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction

For Daily Free Study Material Join wiredfaculty

Wave Optics

A monoenergetic electron beam with electron speed of 5.20 x 106 ms–3 is subject to a magnetic field of 1.30 x 10–4 T normal to the beam velocity. What is the radius of the circle traced by the beam, given e/m for electron equals 1.76 x 1011C kg–1.

Some More Questions From Wave Optics Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A monoenergetic electron beam with electron speed of 5.20 x 10⁶ ms^–3 is subject to a magnetic field of 1.30 x 10^–4 T normal to the beam velocity. What is the radius of the circle traced by the beam, given e/m for electron equals 1.76 x 10¹¹C kg^–1.